Reg Edwards wrote:
The complete equation is -
Attenuation = R/2/Ro + G*Ro/2 Nepers
where G is the conductance of the dielectric, which is small for
materials such as polyethylene and Teflon. And 1 Neper = 20/Ln(10) =
8.686 dB.
Reg, I didn't disagree with your equation. I disagreed with this
statement of yours:
The number one reason for attenuation being higher is because the
conductor diameter is smaller and, as a consequence, its resistance is
higher.
That is simply not a true statement. #13 RG-213 wire is actually
***LARGER*** than #18 ladder-line wire yet the coax still has the
higher matched-line loss. If your statement were true, #13 RG-213
would have lower losses than #18 ladder-line but it doesn't.
The number one reason that coax has higher matched line losses
than ladder-line is NOT primarily due to wire size. It is primarily
due to the differences in characteristic impedance, as I said earlier,
and as proved by your equation above.
--
73, Cecil
http://www.qsl.net/w5dxp
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