Cecil Moore wrote:
Reg Edwards wrote:

The complete equation is -

Attenuation = R/2/Ro + G*Ro/2 Nepers

where G is the conductance of the dielectric, which is small for
materials such as polyethylene and Teflon. And 1 Neper = 20/Ln(10) =
8.686 dB.


Reg, I didn't disagree with your equation. I disagreed with this
statement of yours:

The number one reason for attenuation being higher is because the
conductor diameter is smaller and, as a consequence, its resistance is
higher.

As an illustrated example: Assume a parallel feedline made from #24
wire and having a characteristic impedance of 600 ohms.

What size would the wire in 50 ohm coax have to be to equal the HF
matched line loss of the #24 600 ohm line? (The wire in the coax has
to be 12 times as conductive as the wire in the parallel feedline in
order to offset the effect of Z0.)

A rough estimate indicates that the #24 600 ohm line has approximately
the same matched line loss as RG-213 with its #13 wire.
--
73, Cecil http://www.qsl.net/w5dxp


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