Note also that if the equation for total average power is used to find
average power at any point along the line, fE1 becomes the forward
voltage at the observation point, not necessarily the forward voltage at
the input end of the line. So to calculate the total power as a function
of position along the line, it's probably best to use a voltage at a
fixed point, such as fE2, the forward voltage at the load, in its place.
Make the substitution

|fE1|^2 = |fE2|^2 * exp(2 * ax)

for |fE1|^2 to make the power equation more usable for this purpose.

Roy Lewallen, W7EL

Roy Lewallen wrote:
I've given the equation. With that and a spreadsheet or plotting program
(or graph paper) of your choice, you can have the plot in minutes. Note
that x is the distance from the load.

Roy Lewallen, W7EL

Cecil Moore wrote:

. . .

What does a plot of that extra power look like up
and down the line?