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Old June 26th 05, 10:34 PM
Richard Harrison
 
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Bob, W9DMK wrote:
"The above paragraph was, however, a rather difficult diiffocult to
understand ending---."

Fair enough. Ohm`s law prevails at a-c as it does at d-c. That is, I = E
/ Z, just as I = E / R. If Z is a load impedance, it dictates the
current it accepts. An impedance in series with the load affects the
voltage applied to the load, but whatever voltage to the load is, the
current through the load is related to the voltage adross the load by
Ohm`s law.

When a transmission line feeds a load, Ohm`s law prevails at the load
Feed a certain current through and it produces a certain voltage drop.
Feed a certain voltage and it allows a certain current.

This is repetitious, but it`s true. The line only functions at Zo. The
load only functions at its load impedance. The adjustment between these
two intransigents are the forward and reverse voltages and currents
whose sums make up the actual voltage and current at the load.

Best regards, Richard Harrison, KB5WZI