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Old September 5th 03, 08:58 PM
Cecil Moore
 
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Roy Lewallen wrote:
No, I don't have a problem, nor did I make a mistake. I presented an
example with voltages, currents, and powers that are all
self-consistent, obey Ohm's and Kirchoff's laws, and don't violate any
physical laws. It simply uses those laws, equations that can be found in
nearly any transmission line text, and arithmetic. The analysis is
correct as written.


Nope, it isn't and after following all those laws, you violated one
you should have learned in the 4th grade, i.e. to collect like terms.

You've demonstrated that you're unable to produce a similar analysis
which can be fit into your conception of how things work.


No I haven't. I have produced a simple logical analysis that proved
yours to be wrong. Do you really believe yourself incapable of
making a conceptual error? In the following:

---lossy line---x---1WL 50 ohm lossless line---10+j50 load
Pfwd1-- Pfwd2-- = 30.53W rho=0.82 at 88.9 deg
--Pref1 --Pref2 = 20.53W

I measure ten volts across the ten ohm resistor. I measure 30.53W
forward on the 50 ohm line and 20.53W reflected on the 50 ohm line.
Since the 50 ohm line is lossless, the forward voltage is in phase
with the forward current and the reflected voltage is in phase
with the reflected current. The values of voltages and currents on
the 50 ohm line are easy to calculate. The load reflection coefficient
is easy to calculate. Analysis from 'x' to the load is a no-brainer.

The forward power on the 50 ohm line is 10W less than the reflected
power on the 50 ohm line, i.e. Pfwd2-Pref12 = 10W just as it should.

At point 'x', on the source side of 'x', Pfwd1-Pref1 MUST equal
that same 10W. It doesn't matter what happens between 'x' and the
source. At point 'x', Pfwd1 simply cannot be less than Pref1.

Conditions are the same whether the 1WL of lossless 50 ohm feedline
is in the circuit or out of the circuit. You have not taken all the
forward and reflected terms into account. You have violated something
you should have learned in the 4th grade, i.e. to collect like terms.
Instead, you threw away half of the forward terms and half of the
reflected terms. No wonder you got it wrong.
--
73, Cecil http://www.qsl.net/w5dxp



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