July 21st 05, 08:57 AM
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On Thu, 21 Jul 2005 01:24:36 -0500, (Richard
Harrison) wrote:
Many frequencies (colors) make up the radiation from a light bulb. Much
more heat is radiated than visible light.
Hi Richard,
Actually that is quite wrong. IR is not heat, it is radiation. Heat,
actually phonons, constitutes something less that 10% of the
conversion of electrical power in a light bulb. Lest we take off on
the tangent of IR bulbs being used for heating, it is the load of that
IR radiation (directed upon a dissipative surface) that renders
phonons, otherwise IR is radiated in exactly the same manner as any
radiation. There are any number of simple, practical tests to confirm
this. For one, IR passes through most glass without heating it. You
have to go out of your way to obtain IR blocking glass (which doesn't
even absorb that much either). There are some IR wavelengths that go
right through water, and others that are entirely absorbed.
However, this is not about heat, nor IR, nor even the loss of a
principle vector property, its angle notation, or even the whole
absence of the vector property from the solution to wave interference
powers. Rather, it is about the facade of complete cancellation
Entirely ignoring all these other trivial details, that cancellation
is incomplete in and of necessity for real or imagined initial
conditions. This is revealed in any mathematical solution, and
certainly by examination.
73's
Richard Clark, KB7QHC
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