Richard Clark wrote:
We begin with the model found at:
http://www.qsl.net/w5dxp/weblaser.GIF

Which has been variously described in text as:
1w | 1/4WL |
laser-----air-----|---thin-film---|---glass---...
1st medium | 2nd medium | 3rd medium
n=1.0 n=1.2222 n=1.4938
Pfor=1w Pfor=1.0101w Pfor=1w
Pref=0w Pref=0.0101w Pref=0w
which, of course, is in error

Richard, it would be nice if you retracted your hyperbole since
by now you have realized that everything above is correct, given
the previously stated boundary conditions. You have certainly
successfully demonstrated "The Failure of Poor Concepts in
Discussing Thin Layer Reflections".

I am going to use the same BW correction to find that the un-cancelled
reflection products are TEN TIMES BRIGHTER THAN THE SUN!

There's a magnitude of difference between the *amplitude* reflection
which you mistakenly used and the *power* reflection coefficient,
which you should have used. You will find that the two reflected waves
are exactly the same magnitude (0.01w) and 180 degrees out of phase and
thus cancel to a magnitude of zero in the direction of the source. As I
said before, the reflections from that thin-film are flat black. The
energy components from the wave cancellation join the forward wave
in the thin film.

P1 = 1w*0.99 = 0.99w
P2 = 0.0101w*0.01 = 0.000101w
P1 + P2 + 2*sqrt(P1*P2) = 0.99w + 0.000101w + 0.02w = 1.0101w
--
73, Cecil http://www.qsl.net/w5dxp


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