On 26 Jul 2005 14:54:49 -0500, wrote:

Not sure which indices you are now referring to: n_3=4.0 or 4.04? With
4.0, there is zero reflected light. With 4.04 there is a small amount.

Hi Tor,

It doesn't matter one iota. You can attempt to achieve a perfect
1:2:4 correlation, or any similar relationship that satisfies the
square laws so demanded.

The point of the matter is with such design characteristics fulfilled,
then each interface reflects/transmits in the same proportion. With
each reflecting/transmitting in the same proportion, the second
interface, by the actions of the first, must have less incident upon
it. It then follows that the same proportion of less incident is not
enough to "Totally Cancel" the first interface reflection.

Observing the conservation of energy at the first interface:
X = 0.89X + 0.11X
Observing the conservation of energy at the second interface:
0.89X = 0.792X + 0.098X

0.098X 0.11X

What is even more obvious is that following the second interface, you
have lost roughly 20% of that incident upon the first interface.

There is not enough energy at the second interface, reflected back, to
"Totally Cancel" the energy in the reflection of the first interface.
There can be no other outcome.

That difference yields first interface reflection products that have:
1200 TIMES MORE POWER THAN THE SUN!

73's
Richard Clark, KB7QHC