Richard Clark wrote:

On 26 Jul 2005 14:54:49 -0500, wrote:
Not sure which indices you are now referring to: n_3=4.0 or 4.04? With
4.0, there is zero reflected light. With 4.04 there is a small amount.

It doesn't matter one iota.

Of course it matters. The 1,2,4 combination meets the necessary and
sufficient conditions for the elimination of reflections in medium 1
assuming a steady-state lossless system, i.e. perfectly matched.

The point of the matter is with such design characteristics fulfilled,
then each interface reflects/transmits in the same proportion. With
each reflecting/transmitting in the same proportion, the second
interface, by the actions of the first, must have less incident upon
it.

That is simply not true, Richard. You obviously have not read my
Melles-Griot web posting and/or simply don't understand it. The
forward power in medium 2 is greater than the forward power in
either medium 1 or medium 3. You keep making that same mistake
over and over and over. Why don't you simply take time to
understand the truth?

What is even more obvious is that following the second interface, you
have lost roughly 20% of that incident upon the first interface.

But you have gained the energy involved in the wave cancellation
in medium 1. The forward power in medium 2 is higher than it is
in medium 1. You don't actually believe the BS by some gurus on
this newsgroup that standing waves don't contain any energy, do you?

There is not enough energy at the second interface, reflected back, to
"Totally Cancel" the energy in the reflection of the first interface.
There can be no other outcome.

Only in your mind, Richard, only in your mind. The outcome in reality
is complete cancellation of the reflections in medium 1 assuming
1,2,4 indices of refraction.

That difference yields first interface reflection products that have:
1200 TIMES MORE POWER THAN THE SUN!

Somebody get the net!
--
73, Cecil http://www.qsl.net/w5dxp

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