Richard Clark wrote:
And true for ALL accumulated reflections there after. Reflections do
not add any energy to the cup when the first interface is draining it
more quickly.

If the first interface is a Z0-match, it is not "draining it"
at all. That's what you are missing. The examples have been
for matched systems. If you change your medium 3 to an index
of refraction of 4.0 instead of 4.04, your example is *perfectly
matched* and the first interface is NOT draining the system
because all reflections are canceled. 100% of the source power
is being delivered through the first interface because of that
wave cancellation. At that point it is being joined by the
reflected power so the forward power in the second medium is
greater than the source power. In the second medium, forward
power equals source power plus reflected power. In your example,
source power is one watt, forward power in the second medium is
1.125 watt, and reflected power in the second medium is 0.125 watt.

My analysis allowed ALL of the energy in the reflection from the
second interface ( 0.098X) to combine with the first reflection
(0.11X). This total superposition ...

Power cannot be superposed. If you are going to deal with power,
you need to use the interference equations for power calculations.
Or alternately, convert the powers to voltages, superpose the
voltages, and then calculate the power from the superposed voltage.
That's what most RF engineers do and it works well.

As an optical engineer, I've dealt with the harsh reality of this myth
of total reflection cancellation.

Since you don't understand the physics, it is no wonder that you
failed to accomplish total reflection cancellation. And total
reflection cancellation is easier to accomplish in a transmission
line than it is with light in air.
--
73, Cecil http://www.qsl.net/w5dxp

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