RadioBanter - View Single Post - phase angle and impedance of resonant circuits

August 31st 05, 08:23 AM

wrote:
"When you get finished,
the distance from the origin to the tip of the last vector is the
magnitude of the admittance (1/|Z|) and the angle from the real axis is
the angle of the admittance. This is the negative of the angle of the
impedance."

Do you mean that the angle the admittance is in the opposite quadrant
of the impedance?

If the angle of the admittance is 20 degrees, the angle of the impedance
is -20 degrees. Draw a set of axes. Draw a vector at an angle of 20
degrees from the real (horizontal) axis (20 degrees counterclockwise
from the axis). Now draw another vector at an angle of -20 degrees from
that axis (20 degrees clockwise from the axis). Are they in opposite
quadrants?

Roy Lewallen, W7EL