I found a possible solution:

- with the receiver tuned at 14,139 kHz, the local oscillator works at =
14,139+1,650=3D15,789 kHz
- should the local oscillator also have a component at half its =
frequency (i.e. 7,894.5 kHz), that component would convert an incoming =
9,545 kHz signal to the 1,650 kHz IF
- this method also applies to the other two frequency cases=20

Any ideas on the reason and on the cure?

73

Tony I0JX / K0JX