RadioBanter - View Single Post

October 15th 05, 05:25 AM

wrote:
4.17 watts does not flow back thru the Bird as reflected power, and
the Bird, of course acknowledges.

Yes, I later realized that the Bird's internal feedline forms a
50 ohm Z0-match. Interference at the input and output of the Bird
causes no reflected energy to flow through the Bird. The reflected
energy from the load is re-reflected at the Bird output. The input
of the Bird causes reflections on the source side of the Bird. I
actually calculated all the interferring signals.

I acknowledge that the Bird does not report the actual forward/reverse
power in this example

That was the main point. If the Bird is embedded in something other
than a 50 ohm environment, it does not report the actual forward/reverse
power on the coax on either side of the Bird.
--
73, Cecil http://www.qsl.net/w5dxp