The point is that the loop's inductive reactance is on the order of 10
ohms in the frequency range you're talking about. When resonated with
a capacitor, if the Q is, say, 300, then the impedance at resonance
will be about 3000 ohms, resistive, as seen across the capacitor.
Reg's program gives you an estimate of what it will be. If you put a
low-resistance load across that, the Q will drop drastically. And if
you put your 2 ohms (which it won't be at the received frequency, if I
understand what you have) in series with the loop and capacitor, it
will also drastically lower the Q. So my question remains: how will
you couple to the loop and maintain the Q?

When you measure the input impedance of your detector, you should do it
while the detector is operating, and do it versus frequency. I expect
you'll see a large increase in impedance at the operating frequency.

Cheers,
Tom