In a series resonant circuit, at resonance it is equivalent to a dead short
(disregarding the R of the circuit). Series resonant circuits are usually
used as traps. To develop a voltage one needs a parallel resonant circuit at
the resonant frequency, The Q will simply determine how quickly the voltage
falls off each side of resonance.

Next there are two types of Q, first the calculated unloaded Q and second
the in circuit or loaded Q.

I think you are heading down the wrong path with the series circuit as your
fighting a loosing battle. Assuming a perfect coil and capacitor you create
an infinite Q circuit. Now you hook it up in your circuit. First there has
to be enough resistance to develop the voltage , and here is the rub, as you
increase the resistance to develop a voltage you decrease the Q. Yuk!

Go with a parallel circuit like the rest of the world uses and you will be
going in the right direction.

TRABEM wrote in message ...
On Thu, 27 Oct 2005 14:55:32 -0400, "Fred W4JLE"
wrote:

May I ask, what is with the almost fanitical adherence to Q?

Sure, it's a fair question.

I have a simple receiver with a low impedance input that is few with a
toroid transformer and a tuned circuit to match the impedances and to
keep out of band signals out.

I want to convert the receiver from HF to VLF (60 KHz) and to use a
series tuned loop of high Q as an antenna. In order to simplify the
receiver input, I have mentioned as an option to eliminate the 50 ohm
matching transformer and the tuned circuit in the front end of the
receiver....and to feed it directly with my low impedance loop. In
this way, the loops high Q would serve as the only means of preventing
out of band signals from getting into the receiver.

In order to make sure that actually happens, I suggested making the
loop Q as high as possible.

Hence my 'almost fanatical adherence to Q'

Not sure if it will work, but wanted to run it past the group.

Regards,

T