I agree with the E field computation at 1km. NEC2 calculates the
normalized peak E field as 425.452 V/m, which gives 300 mV/m at 1 km. The
input impedance, with 50 segments (#14 AWG, perfect conductor) is 1.747 -
j823.798 ohms. The NEC output files shows the TRP at 1 kW.

For some reason I seem to get a different received power. If I model a 1
meter monopole, above a perfectly conducting ground, loaded at the base
segment with the complex conjugate of 1.747 + j823.798, and an incident
peak E field of of 1V/m. NEC computes the peak base current as 0.28636 A.
Dividing by 3.3333, for the equivalent RMS current from 300 mV/m RMS
gives: 0.08591 A RMS. power in the load then equals 12.9 mW, which seems
to agree with Reg's figure.

Frank

PS -- NEC computes the gain of a 1 meter, ideal conductor, monopole above a
perfectly conducting ground, as 4.8 dB (Ground wave). Also note the current
in the base, from an incident peak E-field of 1V/m is 0.28636A, which
through 1.747 ohms, is 0.5 V peak. This appears to agree exactly with Reg's
rational.

Frank