Roy Lewallen wrote:

Yet you've found it impossible to explain, either numerically or in
equation form, which "power wave" these "interference terms" belongs to,
or how this "interference" comes about in your model of superposing,
traveling power waves.

For the record, I don't superpose things that lack phase. But if you
turn on two 100 watt light bulbs, don't you double the light output?
This stuff is all explained in _Optics_, by Hecht.

The explanation is indeed simple -- as long as you can continue to avoid
explaining it.

It is all explained in Chipman's "Transmission Lines". Please take the time
to read it and understand it. Just as the voltage and current increase depending
upon the 'Q' of a resonant circuit, the same thing happens with reactive
transmission lines. I am not going to waste my time explaining such an easy
concept. You probably can simulate the situation by drawing the dividing
plane between the cap and the resistor in the following circuit.
|
RF source----//----capacitor---|---resistor------inductor-------+
| | |
+-------//----------------|--------------------------------+
|
plane

The voltage across the capacitor or inductor, depending upon the 'Q' of
the circuit, can be greater than the RF source voltage. You can add 1WL
of transmission line at the '//' point without changing anything. In this
case, the energy exchanged between the capacitor and inductor travels through
the resistor and contributes to power dissipation in the radiation resistance
(if that is what that resistance is). Like I said before, it's a no-brainer.
Once I read Chipman's explanation, it was as clear as day.
--
73, Cecil http://www.qsl.net/w5dxp



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