"Richard Harrison" wrote in message
...
Reg wrote:
"So we have a generator with open-circuit volts of 300 mV, with an
internal resistance of 1.944 ohms, into an Rx load resistance of
1.944
ohms---."

You lose 1/2 the open-circuit voltage in a matched antenna`s
radiation
resistance. 1/2 the voltage in the receiver`s input resistance
causes
1/2 the current. Received carrier power is only 1/4, or in other
words,
6 db less than twice the voltage would produce were it available
across
the receiver`s input resistance.

0.15 volts squared over 1.944 ohms = 0.01157 watts on my Chinese
calculator

=====================================

Yes Richard, I fully agree.

The trouble is that there are other ways of calculating receiver input
power, seemingly equally valid. But they give an input power exactly
1/4 as big or 6 dB less.

Which way is correct? Terman, Kraus, Balani, their Bibles and
numerous computer programs are all at loggerheads with each other.
The very foundations of radio engineering are being undermined. ;o)
----
Reg.