On Tue, 20 Dec 2005 22:06:56 +0000 (UTC), "Reg Edwards"
wrote:

I normally reply, if I reply at all to your idiotic statements, with
"Phooey".

Ah yes, Punchinello,

As gracious as ever.

it should be said
Well, you generally fill the gap the
that the voltage induced in a circular loop is altogether different
which is redundant to the following:
and very much smaller from that induced in a straight wire of the same
length.

Notably you say nothing of how much.

For the sake of novices for whom you have such paternal feelings (but
absolutely no answers) I would offer that the solution in the loop
(that same wire bent over to touch ground) and loaded with 200 Ohms
(not an open) reveals a voltage that need only be multiplied by 20 to
obtain the correct value. Trivial! And what is more, far simpler to
measure across 200 Ohms than an open at 20MHz.

Thus in response to the question:
On Tue, 20 Dec 2005 14:40:14 GMT, Andy Cowley
wrote:
And just how are you going to measure that voltage without getting an
opposite voltage in your voltmeter leads.
has been responded to fully, with a realizable design (barring this
folderol of perfect ground) and removing the objection for meter
leads. It takes no more software than the free version of EZNEC
(zipped up, but it works).

Have a miserable Christmas!
That will be all too true with a visit to and through several of our
nation's airports here soon. ;-(

XOXOXOXOX,
Richard Clark, KB7QHC