Dr. Slick wrote:

Cecil Moore wrote in message ...

Radio913 wrote:

How does a capacitor reflect more power than you feed it?

With an inductor in the circuit, the voltage on a capacitor can
be greater than the source voltage. Consider the following series
resonant circuit. What are the voltages on the cap and coil at
resonance?

100W source========1wl feedline===cap===50 ohm===coil

Is that a 50 ohm resistor? And where is the ground?

Yes, a 50 ohm resistor. No ground, it is a balanced system. Note
the two parallel wires.

Could you re-draw this, Cecil?

Sigh ...

+------1WL feedline--(-j500)--+
| |
100W source (50+j0)
| |
+------1WL feedline--(+j500)--+

--
73, Cecil http://www.qsl.net/w5dxp



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