wrote:
So again, it works in the specific, but not in the general case.

Uh Keith, *NO* instrument works in the general case. Can you
measure gamma rays with your RF voltmeter?

The answer appears orthogonal to the question.

Nope, you are always free to misuse and abuse any instrument,
including a Bird wattmeter.

Go back 3 sentences and re-read "reflected VOLTAGE waves and CURRENT
waves do exist". I think you were quoting from something I wrote.

Yes, I was and it is good to see you have changed your mind on that
one. Now all you have to do is convince us that reflected voltage
waves along with their accompanying E-fields and reflected current
waves along with their accompanying H-fields do not result in
(E x H) = power. Can you prove that the E-fields and H-fields in
a reflected wave are not orthogonal?

I am unsure how you extrapolate this from my writings.

It's easy. During steady-state for a Z0-matched system, the transmission
line with an SWR of 5.83:1 contains three times as much energy as is being
delivered by the source to the load. If the reflected and re-reflected waves
contain no energy, exactly where is that extra energy located? It cannot
stand still.

So you are agreed: The reflected POWER model does not work in general.

As long as resonance effects are taken into account, the reflected power
model works in general. Your Vf*Ir and Vr*If terms don't exist which can
be proven by a laser experiment.

No. You have made an incorrect implication. 100 watts flowing says
nothing about how much energy is stored.

Oh yes it does!!! Given the SWR is 5.83:1, three times as much energy as
a 100 watt source will supply, is stored in the transmission line. If
you hadn't ignored my earlier one-second long transmission line thought
experiment, you would know that by now.

Your experiment appears to be incompletely or incorrectly specified.
If the source is Z0 matched to the transmission line, how did you
get a re-reflected wave at the source?

That's what Z0-matches do - re-reflect all the reflected power back
toward the load. That's how antenna tuners work. Given the SWR, one
can easily calculate exactly how much extra energy exists in an even
multiple of lossless half-wavelengths. (An even number of half-wavelengths
avoids calculus).
--
73, Cecil http://www.qsl.net/w5dxp



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