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Old April 7th 06, 08:04 PM posted to rec.radio.amateur.antenna
Cecil Moore
 
Posts: n/a
Default Current across the antenna loading coil - from scratch

wrote:
You can weave a little tidbit of fact into a big misconception or
diversion if you like, but don't expect others to buy into the
misconception.


When are you going to discuss the technical difference
between I(x,t)=Io*cos(kx+wt) and I(x,t)=Io*cos(kx)*cos(wt)?
The only place those two currents are equal is when x=0. At any
other point, they are virtually opposites of each other. The
differences in those two equations is what led you to believe
the currents at each end of a coil are identical based on
measurements. You guys used a signal, the standing wave current
signal, that is incapable of distinguishing a phase shift even
in a wire, much less in a coil.

The current you measure with a clamp on meter or any other reliable
current meter that does not greatly perturb the circuit is the current
that causes radiation, it is the current that causes heating, and it is
the current we would use to calculate power.


There's absolutely no argument about that. Both forward waves and
reflected waves radiate so standing waves obviously radiate. Both
forward waves and reflected waves cause I^2*R losses. Stating such
obvious technical facts is a diversion and a waste of words.

The phase of that current is the phase of the current that causes
radiation, heating, and that we would use to calculate patterns.


The phase of standing wave current is unchanging. That's why we
get broadside radiation from a 1/2WL standing wave dipole and
end fire radiation from a traveling wave antenna. But again,
stating such obvious technical facts is a diversion and a waste
of words.

When are you going to discuss the actual technical issues?
--
73, Cecil
http://www.qsl.net/w5dxp