Jim Kelley wrote:
Cecil Moore wrote:
Consider the following:
Source---50 ohm feedline---+---1/2WL 150 ohm---50 ohm load
Isn't the 50 ohms that causes rho=0 on the 50 ohm feedline
simply the V/I ratio at point '+'?
The nature of things a point '+' are undefined,
Nope, they are not. The V/I ratio at '+' equals 50 ohms.
so I can't address
that. But according to the way you defined the problem, the
characteristic impedance of the 50 ohm feedline is 50 ohms. That sets
the V/I ratio. The impedance is determined by the distributed
capacitances and inductances of the transmission line - not by the
voltage you put across it. Is there some other way I'm supposed to look
at it?
There are no reflections on the 50 ohm feedline because it "sees" 50
ohms at point '+'. The 50 ohms seen at point '+' is a V/I ratio equal
to 50 ohms. So V affects rho. And rho causes that same V? See
the circular logic?
--
73, Cecil
http://www.qsl.net/w5dxp
-----= Posted via Newsfeeds.Com, Uncensored Usenet News =-----
http://www.newsfeeds.com - The #1 Newsgroup Service in the World!
-----== Over 100,000 Newsgroups - 19 Different Servers! =-----