Yuri Blanarovich wrote:
....
yep, "hope" with pictures, measurements and descriptions (no good)
vs. "experience" = it can't be, but, but, but... ("proof")
how does the coil have higher current at the top if it loses radiation
through capacitance to W8JI? "Experienced" silencio!!! There is your sign!

....

Yuri da BUm

Hi Yuri,

Yesterday I posted in this thread a very simple ideal lumped-circuit
specific example of how it happens. Have a look for that. Consider
the capacitance in that lumped circuit to be part and parcel of the
coil in the distributed case, so you can't in the distributed case
separate its current from the coil current; all you see is the current
going in the "input" terminal (1.3 amps, per Cec's request) and the
current coming out the "output" terminal (2.1 amps) into a load
impedance. If you don't overconstrain the problem (that is, if you
don't specify anything beyond reasonable input and output currents and
load impedance) I can show you a lumped circuit with only series
inductance, series resistance to represent loss if you wish, and shunt
capacitance, that will do the same thing with respect to terminal
currents.

It really is not a stretch at all to get more current coming out than
going in. It WOULD be a stretch to have more power dissipated in the
load than you put in the network, but that's not what's happening, of
course.

Is that all specific enough for you, or would you like to give me a
challenge with a different set of input and output currents and load
impedance (which agrees with what you might actually observe in an
antenna-with-loading-coil situation, and not some ridiculous impossible
set)? I'll even embed the capacitance in the circuit so you won't be
able to say you could measure its current separately from that of the
coil. It's a somewhat pointless exercise, but good mental stimulation,
like working a crossword puzzle, so I'm up for it.

(I trust you didn't really mean that the coil loses radiation
_directly_ to W8JI in your posting quoted above! If every loading coil
in the world did that, poor Tom would be getting pretty warm, I
suppose. In any event, PLEASE UNDERSTAND THIS: the displacement
current from the coil is mostly NOT losing power to the outside world.
Like current in more tangible capacitors, it represents stored energy
that's put into an electric field in part of the cycle, only to be
almost all returned in another part.)

Cheers,
Tom