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Old May 4th 06, 07:31 PM posted to rec.radio.amateur.antenna
Cecil Moore
 
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Default Wire diameter vs Impedance


"Roy Lewallen" wrote:
The
radiation, he says, can be modeled as either a terminating impedance or
as a distributed impedance (R and L) along the line. You can find an
abbreviated version of this explanation in Kraus' _Antennas_.

A transmission line is similar to an antenna in only some respects, and
assuming they act exactly the same leads to erroneous conclusions. Among
the many mistakes made in recent postings is the assumption that a
complete reflection takes place from the end of an antenna wire. As
Schelkunoff, Kraus, and others explain, this isn't correct.


What they seem to be saying is that a quarter-wave monopole
could be modeled like this:

======1/4WL 600 ohm line======12K load

The 12K load dissipates approximately the same amount
of power radiated by a 1/4WL monopole so the conditions
at the feedpoint will be similar to the 1/4WL monopole.

Just because it can be modeled in that fashion doesn't mean
that the radiation is from the same place as the 12k load.

This does seem to be a good way to understand the forward
and reflected waves occurring in a 1/4WL monopole. Guess
what the feedpoint impedance is?

Another way to model the antenna would be with resistance
wire instead of transmission line wire. Then we wouldn't need
the 12K load resistor. We could just specify 1 dB loss between
the forward power and reflected power.
--
73, Cecil, W5DXP