100 Ohm Twin Lead
On Wed, 17 May 2006 12:13:57 GMT, Cecil Moore
wrote:
It didn't. It changed to 56.25 ohms. The load is 100 ohms
and the Z0 is 75 ohms so the SWR is 1.33:1 at the current
minimum/voltage maximum point. To find the impedance 1/4WL
away, divide Z0 by SWR, 75/1.33 = 56.25 ohms.
Thanks, I understand how that works now.
--
73 for now
Buck
N4PGW
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