I've lost the original question.

But there is a lossless transmission line 1 second long.
With a velocity factor of 1.0 it is 30,000 kilometres long.

Let Zo = 100 ohms.
Let applied volts = 100 VDC.
Let terminating resistance be 100 ohms.

Line Inductance = 10,000 Henrys.
Line Capacitance = 1 Farad.

Under steady state conditions -
Line current = 1 amp.
Energy stored in inductance = Sqr(I)*L/2 = 5000 Joules.

Volts across capacitance = 100 volts.
Energy stored in capacitance = SqrV)*C/2 = 5000 Joules.

Total energy stored = 10, 000 Joules = 10,000 watt.seconds.

Which has nothing whatsoever to do with all this nonsense about
reflections. Note that energy in inductance equals energy in
capacitance.

(I trust I have not made a mistake with the arithmetic.)
----
Reg.

"Cecil Moore" wrote in message
. net...
"Buck" wrote:
I can't tell you how many joules are in my coax, but, if you ask,
I
can tell you how many jewels are in my logbook.

This is not aimed at people who don't care about such things.
This is aimed at people who do care about such things especially
those who are disseminating false technical information about
such things.

Some say that since there's 100 watts in and 100 watts out
during steady-state, there's nothing left over for the reflected
waves. They apparently forgot about the time immediately
following power up when there was 100 watts in and less
than 100 watts out.
--
73, Cecil, W5DXP