chuck wrote:


As Roy pointed out, one reason seawater "works" despite its low
conductivity relative to copper is that a high percentage of the
"ground" return current is concentrated very close to the antenna where
path conductance is high. If the water path from the surface to the
Dynaplate is vertical (four feet) does that mean return currents must
travel along four additional feet of seawater (at the hull-water interface)
and thus will encounter greater losses than if
the Dynaplate were at the surface?

OOPS!

"pass through" should be changed to "travel along"
and the parenthetical expression (at the
hull-water interface) should be added for
clarification. Text above has been so edited.

Sorry about that.

Chuck

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