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Old June 6th 06, 03:30 AM posted to rec.radio.amateur.homebrew
David
 
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Default Matching to Crystal Filter

Andy,

Thanks. I am using single-ended output from the SA602 as well as for the
SA605 input. I decouple the unused output/input with 100n Cap in each case.

How do you know the match is working correctly ? My concern is that when
I build the circuit and sweep it with a sig gen and tune it for peak,
how do I know the match to is correct in the first place.

Regards

David


Andy wrote:
David wrote:
Andy,

Thanks for the information. So my matching circuit may look like....

Mixer Out(1k5) - Series coupling cap(1n) - Var L to ground - C-Tap
across L - Crystal Filter - C-Tap - var L across C-Tap - Coupling
C(1n) - SA605 Input (4500//3.5 pF)

C-Tap caps to ground are also tuneable.

I suppose the Q of the match would not need to be particularly high as
the selectivity is provided by the Crystal filter.

Regards

David


Andy writes:

There is a formula for the required Q to perform the match.

Qreq'd = Square Root of ( (Rhigh/Rlow ) - 1 )


1500
or Sqrt of ( ------------ - 1 )
800

It's been a while so, if I got this wrong, I am sure some of the
local RF engineers will correct me...

Anyway,,, this is the minimum Q required in the tank to allow the
match
to be accomplished....

This comes from the equvalency formulae for series to parallel
comversion:


2 2
2
Rp = Rs ( Q + 1 ) Xp = Xs ( Q + 1) / Q

for coverting parallel resistance or reactance into equivalent
series resistance or reactance.....

Sure you can use Z and Y, but the above are much much easier.....


I can't follow your diagram very well, but I think you have it....
... I am assuming SINGLE ENDED OUTPUT. For balanced
output, it is different...

Andy W4OAH