RadioBanter - View Single Post

June 18th 06, 03:55 PM posted to rec.radio.amateur.antenna

wrote:
The "dc path eliminates noise" and the "noise comes from each particle
hitting the antenna and a dc path reduces it" are nearly as far
fetched.

I already explained that to you, Tom. Perhaps you missed it.
In the following diagrams, CH is the charge transferred to
the antenna by a charged particle or any other means.

Given a non-folded dipole, any equalizing of the charge between
the two identical dipole elements must flow through the link
where the noise is picked up by the receiver.

-------CH------+ +---------------
| |
/ /
| |
Link to
receiver

Turning the non-folded dipole into a folded dipole provides
a *local DC path* between the two elements. Most of the
noise will follow that DC path between elements instead of
traveling down the transmission line, through the link, and
back up the transmission line. Hint: Ohm's law.

DC path between elements
+-------------------------------+
+-------CH-----+ +--------------+
| |
/ /
| |
Link to
Receiver

You avoided replying to this last time. One wonders why.
Please explain why you think the charge on the folded dipole
would not take the DC path of least resistance.
--
73, Cecil http://www.qsl.net/w5dxp