2MHz stepup transformer formula ?
Georg,
If you transform a 20VAC signal from a 50 ohm source into a 250VAC signal,
the 250VAC output will be at an impedance of about 7,800 ohms (conservation
of energy; Po = Pin). At this high impedance you won't be able to drive
virtually any length of coax, even open-circuited, as just a few tens of pF
of cable capacitance will cause a significant rolloff at 2 MHz. What load
impedance do you intend to drive?
BTW, 20Vpp at 50 ohms out of your 'signal generator' is quite a signal -
about 1 watt. Is this really the case?
Joe
W3JDR
"Georg Holderied" wrote in message
...
I need to build a transformer that transforms the output of a signal
generator (0.5-2 Mhz 0-20Vpp into 50 ohms) into two opposite phases
at 0-250V.
Load is a few picofarads and a short length of shielded cable.
Where can I find formulas for winding such a transformer ?
Is it preferable to build it as an air or on a ferrite core ?
What ferrite material would I use ?
BTW the signal is used for driving multipole ion traps.
I am an electrical engineer but have not much experience with RF.
George
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