Radial attenuation
On Tue, 25 Jul 2006 12:22:38 +0100, "Reg Edwards"
wrote:
Cecil,
There has been a temporary improvement in my Alzeimer's affliction.
The attenuation along a radial is given by =
Attenuation = ( R / Ro + G * Ro ) / 2 nepers.
Where -
R = HF Conductor resistance.
G = Shunt leakance or conductance, related to soil conductivity.
Ro = Resistive component of line impedance Zo.
One neper = 8.686 dB.
If I published the source code you would be asking even more questions
and Richard Clark would again unjustly accuse me of trolling. ;o)
----
Reg.
Hi Reg,
I believe your temporary Alzhiemers affliction began some time ago, when you
repeatedly reminded me that BLE forgot to indicate the ground conditions. Even
though the conditions are irrelevant when sufficient radials effect a
near-perfect ground, you either skimmed BLE too quickly, or the Alzhiemers
effect had already taken place. I'm going to quote from two BLE pages below:
"Fig 7 earth conductivity = 0.2 x 10^-4 mhos/cm^3
Fig 8 earth conductivity = 1.0 x 10^-4 mhos/cm^3
Fig 9 earth conductivity = 0.2 x 10^-4 mhos/cm^3
Fig 10 earth conductivity =1.0 x 10^-4 mhos/cm^3"
"Fig 18 shows the distribution of earth loss for G = 22 degrees, and G = 88
degrees, for 15 and 113 radial wires, when the frequency was 3000 kilocycles and
the earth conductivity is 0.2 x 10^-4 mhos per cm^3."
It's true they didn't mention permittivity, but at least they did recognize
conductivity, and reported it.
On the other hand, concerning the difference in results between using BLE or
Radials3, unless I missed the critical point somewhere along the way, perhaps
the difference has been misunderstood, where Radials 3 shows usefulness drops
off more quickly with distance from the radiator than BLE. As I understand it,
when only a few radials are present, the longer length is unnecessary. I now
quote again from BLE:
"Fig. 6 shows the actual current in the earth for the same conditions. These
diagrams show that the ground system consisting of only 15 radial wires need not
be more than 0.1 wavelength long, while the system consisting of 113 radials is
still effective out to 0.5 wavelength."
Does this not agree with Reg's Radials3? If not, please tell me what I'm
missing. (I do not have Radials3, and am only commenting from what I've read in
the various posts.)
Walt, W2DU
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