Denny wrote:
Assume that we put a 1 second squirt at the rate of 100 Joules per
second, into the input end of the line, it is an open line at the far
end, and yank the input end of the line out of the transmitter at
exactly 1 second... Now we have a lossless line with a wave going
forward and a reflected wave coming back... Do you still claim 200
joules?

No, 100 joules/second * one second would be 100 joules in your
above example. In my previous example the 100 joule/sec "squirt"
was two seconds long. Thus, in my example, 200 joules made it
into the one-second long line.

Never having more than 50 joules in any quarter section of line and
certainly not doubling to 200 joules... If you have ever held a slinky
toy between your hands and watched the wave bouncing from hand to hand,
you have seen what happens in the 1 second of line section...

True for your example, but not true for my example. In my example
the 100 watt source was delivering 100 watts for two seconds. Last
time I checked 100 joules/sec * 2 seconds = 200 joules.

At T = 2.00 we have 50 joules in each quarter section of line for a
total of 200 joules, and Cecil is fat and happy... Thinks he has been
vindicated...

But wait! There's more... These Ginsu knifes will slice and dice and
uuunhhh, - oops, wrong topic...
Well, as a thought experiment there is nothing to inhibit me from
pumping another 100 joules into the line in the T = 2.00 to 3.00 time
block, ...

On the contrary - if the frequency is an integer number of
cycles and the feedline is exactly one second long, the source
will see an infinite impedance after two seconds and further
sourcing of energy will be impossible. So I am ignoring the
rest of your posting until you understand that fact. Under
the stated the boundary conditions, it is impossible to shove
any more than 200 joules into the line.

At the end of two seconds, the forward current and the newly
arrived reflected current are 180 degrees out of phase and
cancel each other, i.e. after 2 seconds, Ifor + Iref = ZERO
The reflected voltage arrives back in phase with the forward
voltage and so the voltage at that point equals the voltage
in the 141.4 volt source and zero current flows between those
two equal potentials. There is 200 joules in the transmission
line with no possibility of adding any more. The boundary
conditions limit the energy content of the transmission line
to 200 joules, exactly the number of joules needed to support
the steady-state 100 watts forward and 100 watts reflected.
The laws of physics strike again.

Please rethink your position.
--
73, Cecil http://www.w5dxp.com