Cecil Moore wrote:
Richard Clark wrote:

Gene Fuller wrote:

reversing momentum


Imagine the G forces of that for an infinitesmal 1/10¹² second or so.


The pressure of such a momentum change can be calculated.
From "Optics", by Hecht, 4th edition, page 57:
"When the surface under illumination is *perfectly
reflecting*, the beam that entered with a velocity
of +c will emerge with a velocity of -c. This
corresponds to twice the change in momentum that
occurs on absorption, and hence,"

Pressure of a absorbed wave = S(t)/c

Pressure of a reflected wave = 2*S(t)/c

I'll bet the reason no one can measure the radiation pressure
resulting from your "4th mechanism of reflection" is because it
cancels out with the radiation pressure from the cancelled reflection
in the other direction. Right, Cecil? :-)

73, Jim, AC6XG