On Sun, 08 Oct 2006 13:04:00 -0700, Richard Clark
wrote:

So, time for another simple computation:

What is the temperature of an 80M photon?

Looking forward to your fumble.

The ball lay dormant on the 1 inch line with 2 days to snap it and....

OK, the quick Xeroxed answer from my own posting, some time earlier:

0°K or so close as to be indistinguishable;

For extra credit (sic, nothing extra as nothing was credited to Cecil
in the first place):

What is the actual answer to within NOT ±69%,
but to within one order of magnitude!?

All may note the munificence of allowing up to 1000% error allowable
as a "correct" answer. Certainly the master of Xeroxphotonic-zen
might grasp at a straw? After all, how close do you have to be when
you are already dead-nutz on to zero? :-0

[Hint, when I taught Electronics in the Navy, my students swore I
always had an "Ace-Buster" in the quiz.]

BBBBBBRRRRrrringgggggg!

No point in waiting two days for Cecil's fruitless search for
Xeroxable material - even with a latitude of one order of magnitude
slop above and beyond his usual ±69%.

A Photon in the (bottom of the) 80M band would have the equivalent
temperature of:
60µ°K
for extra credit, the answer would have to have fallen somewhere in
the range:
6µ°K..600µ°K

Still pretty darn cold (and a far sight harder to answer than simply
stating near 0°K which was a sufficient answer in the first round).

This, of course, is simple Black Body radiator mechanics that novices
in Optics would have migrated through in High School. Cecil's Photon
radiator seems to need serious back-flushing.

Dare I challenge our master of Xeroxphotonimetry as to the temperature
of a 10M Photon? It would seem that if you cannot compute the simple
matters of heat, you are certainly the person who needs to ask "Where
Does the Power Go?" :-0

Awaiting more Photonic (no, I did NOT misspell pathetic) nonsense from
Cecil....

73's
Richard Clark, KB7QHC