Cecil wrote,


Tdonaly wrote:
I see you've gone into objection-stopper mode: write something
whether it makes sense or not.

Sorry, my neighbor forced some Amaretto upon me yesterday. The
fact that the voltage is hard to measure doesn't prove that it
doesn't exist. Simply loop the ends of the dipole close together
and measure the voltage with an RF voltmeter. It's a no brainer.
These are copper wires. No need to discuss fields.

During 1/2 cycle, there is an excess of electrons on one end.
During the next 1/2 cycle, there is an excess of electrons on
the other end. A voltmeter measures excesses of electrons between
two wires very well.

Or take a look at the end feedpoint impedance of a 1/2WL
monopole. It's a no brainer to discover that the voltage is high
and the current is low. So what is the feedpoint voltage for a
1/2WL end-fed monopole? EZNEC says it is around 3500 ohms giving
a feedpoint voltage of about 550v for 100w compared to a 1/4WL
monopole's feedpoint voltage of about 60v. Do you not understand
that the voltage to current ratios vary from high to low at 1/4WL
intervals along a wire antenna?

So please tell us how photons manage to light up a florescent
light bulb.
--
73, Cecil http://www.qsl.net/w5dxp


After all this time and all these posts, you're still trying to use
circuit theory to explain electromagnetic phenomena in
situations where length and time, as parameters, just can't
be ignored. Secondly, you haven't even demonstrated that you
took time to digest and understand Tom's original post, which
you responded to with a knee-jerk "Brain fart." That's o.k. for
you. If you really want to believe in a simplified view of
electronics that's fine. But, for the rest of us, all the books,
the research, the mathematics, and the thinking of people
from Faraday to Feynman, actually mean something.
73,
Tom Donaly, KA6RUH