"Richard Clark" wrote in message
...
On Mon, 12 Mar 2007 13:37:00 -0400, "Jimmie D"
wrote:

Your mistake is that you assume the output of the tx is 50 ohms,

Hi Jimmie,

At the risk of yet another, non-quantitative reply I will repeat:
a question that has NEVER been answered by those who know what the
transmitter output Z ISN'T:
"What Z is it?"

in the case
you stated the transmitter must be matched to the impedance it sees
looking
into the transmission line.

THAT is true, and it brings us to the point of all this energy
sloshing around until the antenna finally dissipates it out into the
Æther. It is the reflection off the mismatch of the tuner (the
mismatch seen by the antenna as source to the line going back) that
prevents energy from presenting any destructive results to the source
- the whole point of using a tuner in the first place.

73's
Richard Clark, KB7QHC

Correct but I just want to remember that the purpose of the tuner is to
match the impedance of the transmitter to the impedance of the antenna/
transmission line.The standing waves can be viewed as a reflect voltage, a
reflect current or as a reflected impedance. Besides I thought there had
been enough quanitative analysis of the question and was hoping a simple
answer may be enough to turn on the light bulb for the OP. If he still
wanted to know more I figure he would ask.