On Tue, 20 Mar 2007 10:55:12 -0500, Cecil Moore wrote:

Walter Maxwell wrote:
Some of the posters apparently are
unable to appreciate that the reflected power does not cause heating of the amp, unless the reflected power
detunes the amp and the amp is left detuned from resonance, which of course is not the correct manner of
operating the amp.

Some would say that if "reflected power does not cause heating
of the amp", that proves that there is no power (or energy) in
the reflected waves. Those people obviously don't understand
the role of destructive and constructive interference during
the EM wave superposition process.

In addition, Cecil, the experiment also proves that the reflected power doesn't heat the plate, because the
output source resistance is non-dissipative.

Walt