Ian White GM3SEK wrote:
Nobody is trying to restrict your freedom of thought or speech. Nobody
wants to, and nobody can. But lots of people are hoping, begging,
pleading that you develop the SELF-discipline to follow an argument all
the way through to its conclusion, without jumping outside of the
boundaries you laid down at the start.

Sorry Ian, I don't trust you guys enough to roll
dice in the dark with you and then let you tell
me what value was rolled. :-) You are perfectly
free to play mashed potatoes with RF joules but
please don't ask me to join in. Sometimes I think
you have to be just pulling my leg.

It was Gene who first pointed out the difference
between a traveling wave and a standing wave. Now
he says there is no difference.

Gene Fuller, W4SZ wrote:
In a standing wave antenna problem, such as the one you describe,
there is no remaining phase information. Any specific phase
characteristics of the traveling waves died out when the startup
transients died out.

Phase is gone. Kaput. Vanished. Cannot be recovered. Never to be
seen again.

One can send two coherent light beams in opposite
directions almost collinear to each other and observe
the standing waves. Hecht has a graphic of such in
"Optics". The two light beams, forward and reverse,
emerge past the standing wave space undisturbed and
unaffected by the superposition.

How does your theory hold up when measurement of voltage
and current is impossible and everything occurs in free
space for anyone to observe with his/her own eyes? If it
doesn't work for EM light waves then it also doesn't
work for EM RF waves except as a shortcut.

So please take the above example from optics and show
me how the reverse traveling wave is different on
either side of the standing wave space.
--
73, Cecil http://www.w5dxp.com