"Cecil Moore" wrote in message
...
Dave wrote:
forget power, forget energy, they are products of other calculations.
all that is needed is impedance and voltage OR current. once you know
voltage OR current and the impedance you can calculate all the rest.

What would you do if you were dealing with EM light waves
instead of EM RF waves? Optical physicists don't have the
luxury of dealing with "impedance and voltage OR current".
They are forced to deal with the essence of EM waves which
is photonic energy. They have done it for over a century
and have learned a lot about the nature of EM waves. They
did not "forget power, forget energy".
--
yes they do. but photons are propagating em waves, they aren't currents and
voltages, they are E and B fields. you can do the exact same calculations
using either E or B and the refractive index or epsilon/mu. again, all you
need is 2 of them, and you can compute the third, and then you know it all.