Keith Dysart wrote:
Standard analysis can tell us quite a bit about the situation
without the need for further information. The information
we have:
- Generator with 450 Ohm output impedance

There are a number of techniques to ensure that the
reflected waves encounter an impedance of 450 ohms
but none of those techniques are implemented in
amateur radio transmitters. Your generator is
obviously equipped with a circulator load of 450
ohms, 450 ohm attenuation pads, or some active
feedback. Given that, your analysis is correct but
moot. Your point is already known and accepted by
every initiated person including me.

I freely admit that if the proper circulator load
exists or if 450 ohm attenuator pads exist, they
will dissipate the reflected power by heating
up the circulator load resistor or the pads.

But it's tough to argue that there is no energy in
the reflected waves while they are being used to boil
water.
--
73, Cecil http://www.w5dxp.com