Cecil Moore wrote:
b1 = s11(a1@0deg) + s12(a2@180deg) = 0
Actually, looking at it again, for b1 to be 0, the
following would have to be mathematically true.
b1 = |s11(a1)| - |s12(a2)| = 0
Now square both sides of the equation and see what
you get.
--
73, Cecil
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