On Apr 27, 10:25 pm, Cecil Moore wrote:
Keith Dysart wrote:
Which suggests that if there are two directions of rotation, phasors
don't help much with the solution.

By conventional definition, coherent phasors traveling
in opposite directions are rotating in different
directions, one clockwise and one counter-clockwise.

It would, I think, be more precise to say that the vectors are
rotating. When you change your point of view by rotating
the frame of reference along with the vectors, those vectors
become phasors which do not rotate. Although a little
looseness in the language easily leads to saying that
they do.

Adding a forward wave and a reflected wave of equal
amplitude results in:

E = Eot[sin(kx+wt) + sin(kx-wt)]

By convention, the forward +wt wave rotates counter-
clockwise as the angle increases in the + direction.

I agree. I should have said counter-clockwise in my other
post. Once you jump on the rotor to rotate counter-
clockwise with the vectors, the rest of the world (e.g.
the stator) appears to be going clockwise around you.

By convention, the reflected -wt wave rotates clockwise
as the angle increases in the - direction.

The standing wave equation becomes:

E(x,t) = 2*Eot*sin(kx)*cos(wt)

Which direction is the standing-wave phasor rotating?

Which I will try to answer in a response to your next post.

....Keith