Current in 1/2WL Dipoles
Cecil Moore wrote:
The point I was trying to make on the "Rotational Speed"
thread got lost in semantics so here goes again.
Given - a 75m dipole modeled by EZNEC with 90 segments
in each leg of the dipole. 90 segments was chosen
to correspond to the number of degrees from the
feedpoint. Illustrating 1/2 of the dipole with
0 ohm loads at the following segments:
FP--------23--------46--------68--------90
EZNEC reports the following results:
Feedpoint current: 1 amp at 0 deg
Current at seg 23: 0.9281 amp at -1.06 deg
Current at seg 46: 0.7154 amp at -1.78 deg
Current at seg 68: 0.4049 amp at -2.31 deg
Current at seg 90: 0.0122 amp at -2.76 deg
Since the segment numbers correspond to the
number of degrees, it's obvious that the
segment numbers correspond to the expected
phase shift in the traveling waves.
Question: Assuming the current reported by
EZNEC is a ~cosine function, how does one use
that current to determine the traveling wave
phase shift in the wire?
Cecil,
So soon we forget. In a standing wave antenna the phase is gone, kaput.
I believe you have even quoted me on occasion when it was convenient for
the purpose you had at the moment.
Since the traveling wave phase exists only in your imagination, just
pick a number that supports whatever you are trying to "prove" now.
73,
Gene
W4SZ
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