Dave wrote:

You can do the same with DC - you don't need to use AC at all. Put a 50 V
battery in series with the pure 50 Ohm load and it supplies 50 W. Put it in
series with another load, consisting of a 50 Ohm voltage source in
consisting of a 50 volt voltage source, not a 50 Ohm voltage source!
series with a 50 Ohm load, and it is no surprise it delivers a different
power. Depending on what way you connect the two batteries, the current would
be 0 A or 4 A, and so the power 0 or 200W.
As I said before, 0 or 2A, which gives 0 or 200 W.

Your example, though correct, has little to do with the case being discussed.

In your example it is true that power varies depending on what way you connect
the two batteries, but in all cases the total power dissipated in the loads
remains equal to the total power delivered by the sources.

In the case being discussed instead the power dissipated in the load varies with
NO CHANGE in total power delivered by the sources.

73

Tony I0JX