Richard Harrison wrote:
Art wrote:
"When the situation is right the capacitor/battery releases all its
energy like connecting a terminal to ground or shorting it."

Not quite. The inductance, whose reactance equals the capacitance`s
reactance at resonance, opposes any change in current. It only allows
current to grow exponentially during the cycle by simultaneously
generating a counter emf to oppose the current imposed on the inductance
from outside. The impressed current will lag the voltage across a pure
inductance by 90 degrees. The voltage builds across a pure capacitance
with a 90 degree lag of the current through the capacitance. This is
basic electricity 101.

A little too basic, I'm afraid. The 90 degree current lag applies only
to a steady state sinusoidal voltage. For other waveforms (like ones
you'd get connecting batteries or capacitors) you have to resort to the
more general time relationship v = L * di/dt. (Or, if inductance is
changing with time, v = d/dt (L * i).)

Roy Lewallen, W7EL