Richard Clark wrote:
On Wed, 21 Nov 2007 14:00:39 GMT, Cecil Moore
wrote:
What is the momentum of 50.95 W?
momentum? Please be specific.
ditto. :-)
If 50.95 watts is the Poynting vector, actually
watts/unit-area, then the momentum is 50.95/c^2.
Please reference pages 56,57 of "Optics", by Hecht,
4th edition.
--
73, Cecil
http://www.w5dxp.com