Cecil Moore wrote:
Tom Donaly wrote:
Cecil Moore wrote:
In the meantime, let's see if we can agree if 43.4 degrees
of 600 ohm line is terminated in -j567 ohms, the forward
current will be in phase with the reflected current, i.e.
the impedance looking into the line will be zero ohms. Have
you used any current reflection coefficients recently? :-)

Actually, I have. They're built into the formulas for transmission line
voltages and currents on my calculator.

So are we agreed that a 43.4 degree stub terminated in
0-j567 ohms impedance is electrically 1/4WL, i.e. 90
degrees long?

No, but I agree with myself that whatever voltage is applied to
the input will be canceled by all the reflections in the circuit
adding up to a voltage at said input that will cancel the input voltage.
It's like finding the zeros of a network equation.
73,
Tom Donaly, KA6RUH