AI4QJ wrote:
Once you get to -j567 at the discontinuity (travelling
10 degrees along the 100 ohm line), now you interface with the 600 ohm line.
At that point you have to normalize the -j567 ohms to -j(567/600) = -j0.945
on the smith chart (you normalize to Zo for it to calculate properly). This
abrupt switch increases the angle from 10 degrees to arctan (0.945)) or 43
degrees. I think the effect to look for is that the abrupt impedance change
when Zo changes.

Exactly. Plot -j567/100 and -j567/600 on a Smith Chart and
read the phase shift directly from the wavelength scale
around the outside of the chart.
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73, Cecil http://www.w5dxp.com