On Dec 10, 11:43 pm, "AI4QJ" wrote:
I may have misspoken. Once you get to -j567 at the discontinuity (travelling
10 degrees along the 100 ohm line), now you interface with the 600 ohm line.
At that point you have to normalize the -j567 ohms to -j(567/600) = -j0.945
on the smith chart (you normalize to Zo for it to calculate properly). This
abrupt switch increases the angle from 10 degrees to arctan (0.945)) or 43
degrees. I think the effect to look for is that the abrupt impedance change
when Zo changes. A lumped component is not enough to make the model correct.
Comments welcome

I follow the arithmetic, and it still has a certain attractiveness
but how can it make such a difference how the -j567 is produced.

What if you were offerred 3 black boxes, each labelled -j567?
Would it make much difference what was in them?
How does one compute the phase shift at the terminals?

....Keith